15+x-2x^2=0

Lösung

15 + x - 2 x^{2} = 0

x = - \frac{5}{2}, x = 3

Dezimale

x = - 2.5, x = 3

Schritte zur Lösung

15 + x - 2 x^{2} = 0

Schreibe in der Standard Form

a x^{2} + b x + c = 0

- 2 x^{2} + x + 15 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 15}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 15 = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 ( - 2 )}

Trenne die Lösungen

x_{1} = \frac{- 1 + 11}{2 ( - 2 )}, x_{2} = \frac{- 1 - 11}{2 ( - 2 )}

x = \frac{- 1 + 11}{2 ( - 2 )} : - \frac{5}{2}

x = \frac{- 1 - 11}{2 ( - 2 )} : 3

Die Lösungen für die quadratische Gleichung sind:

x = - \frac{5}{2}, x = 3

x^{2} + 41 = 8 x

so l v e f or x, \frac{k x}{2} + 1 = k x^{2} - x y + (k + 1) x - 1

8 c^{2} + 2 c - 3 = 0

(2 x - 7)^{2} = 0

- 2 x^{2} + 8 = x^{2} - 28