What are the solutions to the equation 6x^2+7x-7=-9 ?

The solutions to the equation 6x^2+7x-7=-9 are x=-1/2 ,x=-2/3

Find the zeros of 6x^2+7x-7=-9

The zeros of 6x^2+7x-7=-9 are x=-1/2 ,x=-2/3

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6 x^{2} + 7 x - 7 = - 9

x = - \frac{1}{2}, x = - \frac{2}{3}

Decimal Notation

x = - 0.5, x = - 0.66666 \dots

Solution steps

6 x^{2} + 7 x - 7 = - 9

Move

9

to the left side

6 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

7^{2} - 4 \cdot 6 \cdot 2 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 6}, x_{2} = \frac{- 7 - 1}{2 \cdot 6}

x = \frac{- 7 + 1}{2 \cdot 6} : - \frac{1}{2}

x = \frac{- 7 - 1}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{2}{3}

(\frac{5}{3})^{1}

x + \frac{2}{3} = 2

\frac{1 - 3 x}{5} - \frac{2 - x}{15} = 2

2 r^{2} - 6 r - 8 = 3

14 < - 2 a + 6 - 2 a

What are the solutions to the equation 6x^2+7x-7=-9 ?
The solutions to the equation 6x^2+7x-7=-9 are x=-1/2 ,x=-2/3
Find the zeros of 6x^2+7x-7=-9
The zeros of 6x^2+7x-7=-9 are x=-1/2 ,x=-2/3