solvefor s,(hs)(x)=(x+5)(x^2-3)

解答

求解

s, (h \cdot s) (x) = (x + 5) \cdot (x^{2} - 3)

s = \frac{( x + 5 ) ( x ^{2} - 3 )}{x h}; x \neq = 0, h \neq = 0

求解步骤

(h s) (x) = (x + 5) (x^{2} - 3)

两边除以

x; x \neq = 0

s h = \frac{( x + 5 ) ( x ^{2} - 3 )}{x}; x \neq = 0

两边除以

h; x \neq = 0, h \neq = 0

s = \frac{( x + 5 ) ( x ^{2} - 3 )}{x h}; x \neq = 0, h \neq = 0

so l v e f or a, a^{2} + b^{2} = (a + b)^{2}

- 2 = 7 (q + 2) + 3 (2 q - 1)

so l v e f or x, 2 y = - 2 x + 2

2 (x - 4) = 4 (2 x + 1)

so l v e f or x, 2 x + 6 y = 24