What is (8x+1)(x-7)>= (2x-3)(4x+5) ?

The solution to (8x+1)(x-7)>= (2x-3)(4x+5) is x<= 8/53

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(8x+1)(x-7)>= (2x-3)(4x+5)

(8 x + 1) (x - 7) \geq (2 x - 3) (4 x + 5)

x \leq \frac{8}{53}

Interval Notation

(- \infty, \frac{8}{53}]

Decimal Notation

x \leq 0.15094 \dots

Solution steps

(8 x + 1) (x - 7) \geq (2 x - 3) (4 x + 5)

Rewrite in standard form

- 53 x + 8 \geq 0

Move

8

to the right side

- 53 x \geq - 8

Multiply both sides by

- 1

53 x \leq 8

Divide both sides by

53

x \leq \frac{8}{53}

10 m^{2} + 52 m = - 10

\frac{2 x + 2}{3} + \frac{5 x + x}{6} = \frac{15 + 2 x}{12}

\frac{11}{15} + (- \frac{3}{4})

\frac{5 ^{4}}{5} + 4

(3^{3})^{3}

What is (8x+1)(x-7)>= (2x-3)(4x+5) ?
The solution to (8x+1)(x-7)>= (2x-3)(4x+5) is x<= 8/53