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受欢迎的代数 >

solvefor a,f=(ax^3+3)/(bx^2-2)

解答

求解

a, f = \frac{a x ^{3} + 3}{b x ^{2} - 2}

解答

a = \frac{f ( b x ^{2} - 2 ) - 3}{x ^{3}}; b x^{2} - 2 \neq = 0, x \neq = 0

求解步骤

f = \frac{a x ^{3} + 3}{b x ^{2} - 2}

交换两边

\frac{a x ^{3} + 3}{b x ^{2} - 2} = f

在两边乘以

b x^{2} - 2

a x^{3} + 3 = f (b x^{2} - 2); b x^{2} - 2 \neq = 0

将

3

到右边

a x^{3} = f (b x^{2} - 2) - 3; b x^{2} - 2 \neq = 0

两边除以

x^{3}; b x^{2} - 2 \neq = 0, x \neq = 0

a = \frac{f ( b x ^{2} - 2 ) - 3}{x ^{3}}; b x^{2} - 2 \neq = 0, x \neq = 0

作图

流行的例子

-17+12n=18-16+11n

- 17 + 12 n = 18 - 16 + 11 n

3 x - 9 = 3 (x - 3)

solvefor x,y+5=7(x-8)

so l v e f or x, y + 5 = 7 (x - 8)

solvefor x,5x+2y=-9

so l v e f or x, 5 x + 2 y = - 9

solvefor x,5x+2y=13

so l v e f or x, 5 x + 2 y = 13