2x^2+12x-32=0

解

2 x^{2} + 12 x - 32 = 0

x = 2, x = - 8

解答ステップ

2 x^{2} + 12 x - 32 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 32 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 32) = 20

x_{1, 2} = \frac{- 12 \pm 20}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 12 + 20}{2 \cdot 2}, x_{2} = \frac{- 12 - 20}{2 \cdot 2}

x = \frac{- 12 + 20}{2 \cdot 2} : 2

x = \frac{- 12 - 20}{2 \cdot 2} : - 8

二次equationの解:

x = 2, x = - 8