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simplificar (15^22549)/(35^2*45^2)

Solución

simplificar

\frac{1 5 ^{2} \cdot 25 \cdot 49}{3 5 ^{2} \cdot 4 5 ^{2}}

\frac{1}{9}

Notación decimal

0.11111 \dots

Pasos de solución

\frac{1 5 ^{2} \cdot 25 \cdot 49}{3 5 ^{2} \cdot 4 5 ^{2}}

Factorizar

1 5^{2} : 5^{2} \cdot 3^{2}

= \frac{5 ^{2} \cdot 3 ^{2} \cdot 25 \cdot 49}{3 5 ^{2} \cdot 4 5 ^{2}}

Factorizar

3 5^{2} : 5^{2} \cdot 7^{2}

= \frac{5 ^{2} \cdot 3 ^{2} \cdot 25 \cdot 49}{5 ^{2} \cdot 7 ^{2} \cdot 4 5 ^{2}}

Eliminar los terminos comunes:

5^{2}

= \frac{3 ^{2} \cdot 25 \cdot 49}{7 ^{2} \cdot 4 5 ^{2}}

Factorizar

4 5^{2} : 3^{4} \cdot 5^{2}

= \frac{3 ^{2} \cdot 25 \cdot 49}{7 ^{2} \cdot 3 ^{4} \cdot 5 ^{2}}

\frac{3 ^{2}}{3 ^{4}} = \frac{1}{3 ^{2}}

= \frac{25 \cdot 49}{7 ^{2} \cdot 3 ^{2} \cdot 5 ^{2}}

Descomponer el número en factores primos:

25 = 5^{2}

= \frac{5 ^{2} \cdot 49}{7 ^{2} \cdot 3 ^{2} \cdot 5 ^{2}}

Eliminar los terminos comunes:

5^{2}

= \frac{49}{7 ^{2} \cdot 3 ^{2}}

Descomponer el número en factores primos:

49 = 7^{2}

= \frac{7 ^{2}}{7 ^{2} \cdot 3 ^{2}}

Eliminar los terminos comunes:

7^{2}

= \frac{1}{3 ^{2}}

3^{2} = 9

= \frac{1}{9}

\frac{2}{9} - \frac{4}{15} + 2

\frac{60}{5}

\frac{x}{x + 4} - \frac{2 x}{x + 2}

sin^{2} (x) + tan^{2} (x) + cos^{2} (x)