化简 (3x^2+x+1)-(2x^2-3x-5)

解答

化简

(3 x^{2} + x + 1) - (2 x^{2} - 3 x - 5)

x^{2} + 4 x + 6

求解步骤

(3 x^{2} + x + 1) - (2 x^{2} - 3 x - 5)

使用法则:

(a) = a

(3 x^{2} + x + 1) = 3 x^{2} + x + 1

= 3 x^{2} + x + 1 - (2 x^{2} - 3 x - 5)

使用分配律:

- (a - b) = - a + b

- (2 x^{2} - 3 x - 5) = - 2 x^{2} + 3 x + 5

= 3 x^{2} + x + 1 - 2 x^{2} + 3 x + 5

对同类项分组

= 3 x^{2} - 2 x^{2} + x + 3 x + 1 + 5

e x p an d 2 a (a^{2} - 7) (a + 2)

s im pl i f y \frac{3}{x - 3} - \frac{5}{x - 2}

s im pl i f y \frac{x + 8}{x ^{2} + 13 x + 40} \cdot \frac{x ^{2} - 25}{9 x ^{2}}

s im pl i f y \frac{( 3 )}{( b - 3 )} + \frac{( b )}{( b - 3 )}

s im pl i f y 6.24 x 1 0^{18} \cdot 240