m^2+5m-14=0

解

m^{2} + 5 m - 14 = 0

m = 2, m = - 7

解答ステップ

m^{2} + 5 m - 14 = 0

解くとthe二次式

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

m_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

解を分離する

m_{1} = \frac{- 5 + 9}{2 \cdot 1}, m_{2} = \frac{- 5 - 9}{2 \cdot 1}

m = \frac{- 5 + 9}{2 \cdot 1} : 2

m = \frac{- 5 - 9}{2 \cdot 1} : - 7

二次equationの解:

m = 2, m = - 7