zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

展开 ((3x+4)^3)/9

解答

展开

\frac{( 3 x + 4 ) ^{3}}{9}

解答

3 x^{3} + 12 x^{2} + 16 x + \frac{64}{9}

求解步骤

\frac{( 3 x + 4 ) ^{3}}{9}

(3 x + 4)^{3} = 27 x^{3} + 108 x^{2} + 144 x + 64

= \frac{27 x ^{3} + 108 x ^{2} + 144 x + 64}{9}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{3} + 108 x ^{2} + 144 x + 64}{9} = \frac{27 x ^{3}}{9} + \frac{108 x ^{2}}{9} + \frac{144 x}{9} + \frac{64}{9}

= \frac{27 x ^{3}}{9} + \frac{108 x ^{2}}{9} + \frac{144 x}{9} + \frac{64}{9}

数字相除:

\frac{27}{9} = 3

= 3 x^{3} + \frac{108 x ^{2}}{9} + \frac{144 x}{9} + \frac{64}{9}

数字相除:

\frac{108}{9} = 12

= 3 x^{3} + 12 x^{2} + \frac{144 x}{9} + \frac{64}{9}

数字相除:

\frac{144}{9} = 16

= 3 x^{3} + 12 x^{2} + 16 x + \frac{64}{9}

流行的例子

展开 U(t-4)(2-t^2)+3e^{-pit}+sin(5t)-t^3

e x p an d U (t - 4) (2 - t^{2}) + 3 e^{- π t} + sin (5 t) - t^{3}

e x p an d 9 (π + 1)

展开 (A+B)(C+B)(D^'+B)(ACD^'+E)

e x p an d (A + B) (C + B) (D^{^{'}} + B) (A C D^{^{'}} + E)

展开 (2x+3)dx+(3x+2y)dy

e x p an d (2 x + 3) d x + (3 x + 2 y) d y

展开 5/((x+2)^2)

e x p an d \frac{5}{( x + 2 ) ^{2}}