展开 (A+B)(C+B)(D^'+B)(ACD^'+E)

解答

展开

(A + B) (C + B) (D^{^{'}} + B) (A C D^{^{'}} + E)

A^{2} C^{2} D^{2'} + A CE D^{'} + A^{2} B C^{2} D^{'} + A BCE + A^{2} BC D^{2'} + A BE D^{'} + A^{2} B^{2} C D^{'} + A B^{2} E + A B C^{2} D^{2'} + BCE D^{'} + A B^{2} C^{2} D^{'} + B^{2} CE + A B^{2} C D^{2'} + B^{2} E D^{'} + A B^{3} C D^{'} + B^{3} E

求解步骤

(A + B) (C + B) (D^{^{'}} + B) (A C D^{^{'}} + E)

乘开

(A + B) (C + B) : A C + A B + BC + B^{2}

= (A C + A B + BC + B^{2}) (D^{^{'}} + B) (A C D^{^{'}} + E)

乘开

(A C + A B + BC + B^{2}) (D^{^{'}} + B) : A C D^{^{'}} + A BC + A B D^{^{'}} + A B^{2} + BC D^{^{'}} + B^{2} C + B^{2} D^{^{'}} + B^{3}

= (A C D^{^{'}} + A BC + A B D^{^{'}} + A B^{2} + BC D^{^{'}} + B^{2} C + B^{2} D^{^{'}} + B^{3}) (A C D^{^{'}} + E)

乘开

(A C D^{^{'}} + A BC + A B D^{^{'}} + A B^{2} + BC D^{^{'}} + B^{2} C + B^{2} D^{^{'}} + B^{3}) (A C D^{^{'}} + E) : A^{2} C^{2} D^{2^{'}} + A CE D^{^{'}} + A^{2} B C^{2} D^{^{'}} + A BCE + A^{2} BC D^{2^{'}} + A BE D^{^{'}} + A^{2} B^{2} C D^{^{'}} + A B^{2} E + A B C^{2} D^{2^{'}} + BCE D^{^{'}} + A B^{2} C^{2} D^{^{'}} + B^{2} CE + A B^{2} C D^{2^{'}} + B^{2} E D^{^{'}} + A B^{3} C D^{^{'}} + B^{3} E

= A^{2} C^{2} D^{2^{'}} + A CE D^{^{'}} + A^{2} B C^{2} D^{^{'}} + A BCE + A^{2} BC D^{2^{'}} + A BE D^{^{'}} + A^{2} B^{2} C D^{^{'}} + A B^{2} E + A B C^{2} D^{2^{'}} + BCE D^{^{'}} + A B^{2} C^{2} D^{^{'}} + B^{2} CE + A B^{2} C D^{2^{'}} + B^{2} E D^{^{'}} + A B^{3} C D^{^{'}} + B^{3} E

e x p an d (2 x + 3) d x + (3 x + 2 y) d y

e x p an d \frac{5}{( x + 2 ) ^{2}}

e x p an d \frac{s ^{3} + 2 s ^{2} + 4 s + 5}{( s + 1 ) ^{2} ( s + 2 ) ^{2}}

e x p an d (5 x^{3} - e^{4 x})^{2}

e x p an d 2 \cdot 1.97 \cdot (1, 7 - 0)