解
展開する (3(x−2y)+2(x+3)=4,)(4(x+y)−3(x+2y)=−2)
解
12x2−12xy−24y2−9=4y2−6x+12y+2=4,4x2+2=4,4xy+2=4,4⋅3x+2=4,4⋅3y−2=4,3=x2−2=4,3=2xy−2=4,3=3x−2=4,3=6y−2=4,2x−2=4,2⋅3
解答ステップ
(3(x−2y)+2(x+3)=4,)(4(x+y)−3(x+2y)=−2)
=(3(x−2y)+2⋅4=,(x+3))(4(x+y)−3=(x+2y)−2)
拡張 (3(x−2y)+2(x+3)=4,)(4(x+y)−3(x+2y)=−2):3⋅4(x−2y)(x+y)−3⋅3(x−2y)(x+2y)=−3⋅2(x−2y)+2(x+3)=4,4(x+y)−2(x+3)=4,3(x+2y)=−2(x+3)=4,2
3⋅4(x−2y)(x+y)−3⋅3(x−2y)(x+2y)=−3⋅2(x−2y)+2(x+3)=4,4(x+y)−2(x+3)=4,3(x+2y)=−2(x+3)=4,2
拡張 3⋅4(x−2y)(x+y):12x2−12xy−24y2
12x2−12xy−24y2−3⋅3(x−2y)(x+2y)=−3⋅2(x−2y)+2(x+3)=4,4(x+y)−2(x+3)=4,3(x+2y)=−2(x+3)=4,2
拡張 −3⋅3(x−2y)(x+2y)=:−9=4y2
12x2−12xy−24y2−9=4y2−3⋅2(x−2y)+2(x+3)=4,4(x+y)−2(x+3)=4,3(x+2y)=−2(x+3)=4,2
拡張 −3⋅2(x−2y):−6x+12y
12x2−12xy−24y2−9=4y2−6x+12y+2(x+3)=4,4(x+y)−2(x+3)=4,3(x+2y)=−2(x+3)=4,2
拡張 2(x+3)=4,4(x+y):2=4,4x2+2=4,4xy+2=4,4⋅3x+2=4,4⋅3y
12x2−12xy−24y2−9=4y2−6x+12y+2=4,4x2+2=4,4xy+2=4,4⋅3x+2=4,4⋅3y−2(x+3)=4,3(x+2y)=−2(x+3)=4,2
拡張 −2(x+3)=4,3(x+2y)=:−2=4,3=x2−2=4,3=2xy−2=4,3=3x−2=4,3=6y
12x2−12xy−24y2−9=4y2−6x+12y+2=4,4x2+2=4,4xy+2=4,4⋅3x+2=4,4⋅3y−2=4,3=x2−2=4,3=2xy−2=4,3=3x−2=4,3=6y−2(x+3)=4,2
拡張 −2=4,2(x+3):−2=4,2x−2=4,2⋅3
12x2−12xy−24y2−9=4y2−6x+12y+2=4,4x2+2=4,4xy+2=4,4⋅3x+2=4,4⋅3y−2=4,3=x2−2=4,3=2xy−2=4,3=3x−2=4,3=6y−2=4,2x−2=4,2⋅3