erweitern e^{t-2}U(t-2)

Lösung

erweitern

e^{t - 2} U (t - 2)

e^{t - 2} t U - 2 e^{t - 2} U

Schritte zur Lösung

e^{t - 2} U (t - 2)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = e^{t - 2} U, b = t, c = 2

= e^{t - 2} U t - e^{t - 2} U \cdot 2

= e^{t - 2} t U - 2 e^{t - 2} U

e x p an d \frac{x ^{5} + 1}{( x ^{2} - x ) ( x ^{4} + 2 x ^{2} + 1 )}

e x p an d 2 e^{- x} x - e^{- x} (x^{2} - 1)

e x p an d y^{''} (x) - 4 x y^{'} (x) + (4 x^{2} - 2) y

\frac{d ^{3}}{d x ^{3}} ((y) (2 x^{2} - \frac{1}{x ^{3}}))

e x p an d \frac{4 e ^{- 2 s}}{( s - 1 ) ( s + 4 ) ^{2}}