展开 (x-2)e^x+1

解答

展开

(x - 2) e^{x} + 1

e^{x} x - 2 e^{x} + 1

求解步骤

(x - 2) e^{x} + 1

= e^{x} (x - 2) + 1

乘开

e^{x} (x - 2) : e^{x} x - 2 e^{x}

= e^{x} x - 2 e^{x} + 1

e x p an d π (e - 1)

e x p an d e^{2 t} u (2 - t)

e x p an d \frac{( 2 x ^{3} + x + 1 ) d x}{( x ^{2} + 9 )}

e x p an d \frac{( 6 x ^{2} - 4 x )}{( ( x + 2 ) ^{2} ( x - 1 ) )}

e x p an d \frac{2 ^{^{'}} s + 3}{( s - 1 ) ^{3} ( s ^{3} + 1 )}