展开 ((2x^3+x+1)dx)/((x^2+9))

解答

展开

\frac{( 2 x ^{3} + x + 1 ) d x}{( x ^{2} + 9 )}

\frac{2 x ^{3} d x + x d x + d x}{x ^{2} + 9}

求解步骤

\frac{( 2 x ^{3} + x + 1 ) d x}{x ^{2} + 9}

乘开

(2 x^{3} + x + 1) d x : 2 x^{3} d x + x d x + d x

= \frac{2 x ^{3} d x + x d x + d x}{x ^{2} + 9}

e x p an d \frac{( 6 x ^{2} - 4 x )}{( ( x + 2 ) ^{2} ( x - 1 ) )}

e x p an d \frac{2 ^{^{'}} s + 3}{( s - 1 ) ^{3} ( s ^{3} + 1 )}

e x p an d (x^{2} + 1)^{2} (2 x) d x

e x p an d (- 8 t^{3} + 68 t^{2} - 204 t + 207) \cdot (- 1, + 2)

e x p an d \frac{( a y + b x ) ( x a + y b )}{( a y - b x ) ( x a - y b )}