erweitern (i(-1)^n)/(2npi)+((-1)^n-1)/(2n^2pi^2)

Lösung

erweitern

\frac{i ( - 1 ) ^{n}}{2 nπ} + \frac{( - 1 ) ^{n} - 1}{2 n ^{2} π ^{2}}

\frac{( - 1 ) ^{n} i}{2 πn} + \frac{( - 1 ) ^{n}}{2 π ^{2} n ^{2}} - \frac{1}{2 π ^{2} n ^{2}}

Schritte zur Lösung

\frac{i ( - 1 ) ^{n}}{2 nπ} + \frac{( - 1 ) ^{n} - 1}{2 n ^{2} π ^{2}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{( - 1 ) ^{n} - 1}{2 n ^{2} π ^{2}} = \frac{( - 1 ) ^{n}}{2 n ^{2} π ^{2}} - \frac{1}{2 n ^{2} π ^{2}}

= \frac{( - 1 ) ^{n} i}{2 πn} + \frac{( - 1 ) ^{n}}{2 π ^{2} n ^{2}} - \frac{1}{2 π ^{2} n ^{2}}

e x p an d 1537.6 \cdot ((s + 0.6) \cdot (s + 0.8))

e x p an d \frac{( S ^{3} - 3 S ^{2} + 6 S - 4 )}{( S ^{2} - 2 S + 2 ) ^{2}}

e x p an d \frac{x ( 2 x - 1 )}{x + 1}

e x p an d (- 7, 1, - 5) t + (3, - 6, - 8) (1 - t)

e x p an d \frac{2 x ^{2} - 6 x + 5}{( x - 2 ) ( 2 x - 4 )}