展开 37sin((2pi)/(365)(x-101))+25

解答

展开

37 sin (\frac{2 π}{365} (x - 101)) + 25

37 sin (\frac{2 π x - 202 π}{365}) + 25

求解步骤

37 sin (\frac{2 π}{365} (x - 101)) + 25

37 sin (\frac{2 π}{365} (x - 101)) = 37 (cos (\frac{202 π}{365}) sin (\frac{2 π x}{365}) - sin (\frac{202 π}{365}) cos (\frac{2 π x}{365}))

= 37 (cos (\frac{202 π}{365}) sin (\frac{2 π x}{365}) - sin (\frac{202 π}{365}) cos (\frac{2 π x}{365})) + 25

使用角差恒等式:

sin (s) cos (t) - cos (s) sin (t) = sin (s - t)

= 37 sin (\frac{2 π x}{365} - \frac{202 π}{365}) + 25

化简

\frac{2 π x}{365} - \frac{202 π}{365} : \frac{2 π x - 202 π}{365}

= 37 sin (\frac{2 π x - 202 π}{365}) + 25

e x p an d π (\frac{16 2}{5} + \frac{16}{3})

e x p an d \frac{2 x + 3}{( x - 11 ) ( x + 4 )}

e x p an d (1 - u^{2} + v^{2})^{2} + 4 u^{2} v^{2} + 4 u^{2}

e x p an d \frac{191700 ( e + 1 ) ( e - 1 )}{e ^{4}}

e x p an d \frac{1}{s ( s - 3 )}