erweitern e^{2(t-1)}cos(w)(t-1)\H(t-1)

Lösung

erweitern

e^{2 (t - 1)} cos (w) (t - 1) H (t - 1)

e^{2 t - 2} t H (t - 1) cos (w) - e^{2 t - 2} H (t - 1) cos (w)

Schritte zur Lösung

e^{2 (t - 1)} cos (w) (t - 1) H (t - 1)

= e^{2 (t - 1)} H (t - 1) cos (w) (t - 1)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = e^{2 (t - 1)} cos (w) H (t - 1), b = t, c = 1

= e^{2 (t - 1)} cos (w) H (t - 1) t - e^{2 (t - 1)} cos (w) H (t - 1) \cdot 1

= e^{2 (t - 1)} t H (t - 1) cos (w) - 1 \cdot e^{2 (t - 1)} H (t - 1) cos (w)

Vereinfache

e^{2 (t - 1)} t H (t - 1) cos (w) - 1 \cdot e^{2 (t - 1)} H (t - 1) cos (w) : e^{2 t - 2} t H (t - 1) cos (w) - e^{2 t - 2} H (t - 1) cos (w)

= e^{2 t - 2} t H (t - 1) cos (w) - e^{2 t - 2} H (t - 1) cos (w)

e x p an d \frac{- l ( - 2 l ( - 2 l ( - 2 l + 1 ) - 1 ) + 1 ) - 1}{8}

e x p an d \frac{( x - 1 ) lo g _{2} ( x )}{1 + x}

e x p an d \frac{3 ( 1 + 5 )}{2}

e x p an d (\frac{( x + 1 ) ( x ) ( x - 2 )}{- 2}) \cdot 3

e x p an d \frac{9 ( x ^{10} - 1 )}{5}