展开 (1-w-w^2)^5

解答

展开

(1 - w - w^{2})^{5}

- w^{10} - 5 w^{9} - 5 w^{8} + 10 w^{7} + 15 w^{6} - 11 w^{5} - 15 w^{4} + 10 w^{3} + 5 w^{2} - 5 w + 1

求解步骤

(1 - w - w^{2})^{5}

(1 - w - w^{2})^{5} = (1 - w - w^{2}) (1 - w - w^{2}) (1 - w - w^{2}) (1 - w - w^{2}) (1 - w - w^{2})

= (- w^{2} - w + 1) (- w^{2} - w + 1) (- w^{2} - w + 1) (- w^{2} - w + 1) (- w^{2} - w + 1)

乘开

(1 - w - w^{2}) (1 - w - w^{2}) (1 - w - w^{2}) (1 - w - w^{2}) (1 - w - w^{2}) : - w^{10} - 5 w^{9} - 5 w^{8} + 10 w^{7} + 15 w^{6} - 11 w^{5} - 15 w^{4} + 10 w^{3} + 5 w^{2} - 5 w + 1

= - w^{10} - 5 w^{9} - 5 w^{8} + 10 w^{7} + 15 w^{6} - 11 w^{5} - 15 w^{4} + 10 w^{3} + 5 w^{2} - 5 w + 1

e x p an d 2 c (4 x y^{3} \frac{d y}{d x} + y^{4})

e x p an d \frac{( x ^{4} - 3 x + 5 )}{( x - 1 ) R x ^{3} + x ^{2} + x - 2}

e x p an d \frac{1}{( x ^{2} + a ^{2} ) ^{2}}

e x p an d 3 x (x = - 1)

e x p an d ln (3 \frac{x + 2}{x ^{4} ( x ^{2} - 4 )})