expand 25pi(2-x/4)^2

الحلّ

expand

25 π (2 - \frac{x}{4})^{2}

\frac{25 π x ^{2}}{16} - 25 π x + 100 π

خطوات الحلّ

25 π (2 - \frac{x}{4})^{2}

(2 - \frac{x}{4})^{2} = 4 - x + \frac{x ^{2}}{16}

= 25 π (\frac{x ^{2}}{16} - x + 4)

فعّل قانون ضرب الأقواس

= 25 π 4 + 25 π (- x) + 25 π \frac{x ^{2}}{16}

فعّل قوانين سالب-موجب

+ (- a) = - a

= 25 \cdot 4 π - 25 π x + 25 π \frac{x ^{2}}{16}

25 \cdot 4 π - 25 π x + 25 π \frac{x ^{2}}{16}

بسّط:

100 π - 25 π x + \frac{25 π x ^{2}}{16}

= 100 π - 25 π x + \frac{25 π x ^{2}}{16}

Rewrite in standard form

= \frac{25 π x ^{2}}{16} - 25 π x + 100 π

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