d/(dt)((x)(t^2+6))

Lösung

\frac{d}{d t} ((x) (t^{2} + 6))

\frac{d x}{d t} (t^{2} + 6) + 2 t x

Schritte zur Lösung

\frac{d}{d t} ((x) (t^{2} + 6))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = t^{2} + 6

= \frac{d x}{d t} (t^{2} + 6) + \frac{d}{d t} (t^{2} + 6) x

\frac{d}{d t} (t^{2} + 6) = 2 t

= \frac{d x}{d t} (t^{2} + 6) + 2 t x

e x p an d \frac{\frac{d}{d x} ( 1 + x ( lo g _{10} ( x ) + 1 ) )}{x}

e x p an d 145447 \cdot (1 - ((- 98.07089)^{0.234957}))

e x p an d \frac{x ^{2} + 15}{( x + 3 ) ( x ^{2} + 3 )}

e x p an d π (- 4 cos (x) + 4)

e x p an d (3 e^{t} cos (t) - 3 e^{t} sin (t))^{2}