展开 A(Bx+Ct+D)^2

解答

展开

A (B x + Ct + D)^{2}

A B^{2} x^{2} + 2 A B D x + 2 A BC x t + A D^{2} + A C^{2} t^{2} + 2 A C D t

求解步骤

A (B x + Ct + D)^{2}

(B x + Ct + D)^{2} = B^{2} x^{2} + 2 B D x + 2 BC x t + D^{2} + C^{2} t^{2} + 2 C D t

= A (B^{2} x^{2} + 2 B D x + 2 BC x t + C^{2} t^{2} + 2 C D t + D^{2})

打开括号

= A B^{2} x^{2} + A \cdot 2 B D x + A \cdot 2 BC x t + A D^{2} + A C^{2} t^{2} + A \cdot 2 C D t

= A B^{2} x^{2} + 2 A B D x + 2 A BC x t + A D^{2} + A C^{2} t^{2} + 2 A C D t

e x p an d (x + 5) e^{2 x}

e x p an d \frac{\frac{d}{d x} ( x ^{3} + 3 )}{( x + 5 ) ^{2}}

e x p an d - 2 - 4 (- 2 b x + c = - 6 x)

e x p an d e^{7 x} (7 - 9 e^{3 x})

e x p an d \frac{d x}{( x ^{2} + a ^{2} ) ^{2}}