展开 limh\Rightarrow 0tan(3)(x+h)-tan(3x)h

解答

展开

l imh \Rightarrow 0 tan (3) (x + h) - tan (3 x) h

0 i tan (3) \Rightarrow l mh x + 0 i tan (3) \Rightarrow l mhh - tan (3 x) h

求解步骤

l imh \Rightarrow 0 \cdot tan (3) (x + h) - tan (3 x) h

= 0 i tan (3) \Rightarrow l mh (x + h) - h tan (3 x)

乘开

l imh \Rightarrow 0 \cdot tan (3) (x + h) : 0 i tan (3) \Rightarrow l mh x + 0 i tan (3) \Rightarrow l mhh

= 0 i tan (3) \Rightarrow l mh x + 0 i tan (3) \Rightarrow l mhh - tan (3 x) h

e x p an d A (- 5, - 4) B (1, 1)

e x p an d \frac{( x + 2 ) ( x - 3 )}{( x - 2 ) ( x - 1 )}

e x p an d \frac{K}{( J s + b ) ( L s + R ) + K ^{2}}

e x p an d \frac{x ( x - 2 )}{( x + 3 ) ( x - 4 ) ^{2}}

e x p an d \frac{( 3 x + 4 ) ^{3}}{3}