展開する-(2x+8x-(3x+6)-(2x+4)=(4x-2-(-6x+2)))

解

展開する

- (2 x + 8 x - (3 x + 6) - (2 x + 4) = (4 x - 2 - (- 6 x + 2)))

- 2 x - 8 x + (3 x + 6) + = 20 x^{2} = 32 x = 16

解答ステップ

- (2 x + 8 x - (3 x + 6) - (2 x + 4) = (4 x - 2 - (- 6 x + 2)))

= - (2 x + 8 x - (3 x + 6) - = (2 x + 4) (4 x - 2 - (- 6 x + 2)))

拡張

- (2 x + 8 x - (3 x + 6) - (2 x + 4) = (4 x - 2 - (- 6 x + 2))) : - 2 x - 8 x + (3 x + 6) + (2 x + 4) = (4 x - 2 - (- 6 x + 2))

- 2 x - 8 x + (3 x + 6) + (2 x + 4) = (4 x - 2 - (- 6 x + 2))

拡張

(2 x + 4) = (4 x - 2 - (- 6 x + 2)) : + = 20 x^{2} = 32 x = 16

- 2 x - 8 x + (3 x + 6) + = 20 x^{2} = 32 x = 16