展开 (13(3x^2-2sqrt(3)xy+y^2))/4

解答

展开

\frac{13 ( 3 x ^{2} - 2 3 x y + y ^{2} )}{4}

\frac{39 x ^{2}}{4} - \frac{13 3 x y}{2} + \frac{13 y ^{2}}{4}

求解步骤

\frac{13 ( 3 x ^{2} - 2 3 x y + y ^{2} )}{4}

乘开

13 (3 x^{2} - 23 x y + y^{2}) : 39 x^{2} - 263 x y + 13 y^{2}

= \frac{39 x ^{2} - 26 3 x y + 13 y ^{2}}{4}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{39 x ^{2} - 26 3 x y + 13 y ^{2}}{4} = \frac{39 x ^{2}}{4} - \frac{26 3 x y}{4} + \frac{13 y ^{2}}{4}

= \frac{39 x ^{2}}{4} - \frac{26 3 x y}{4} + \frac{13 y ^{2}}{4}

消掉

\frac{26 3 x y}{4} : \frac{13 3 x y}{2}

= \frac{39 x ^{2}}{4} - \frac{13 3 x y}{2} + \frac{13 y ^{2}}{4}

e x p an d p ro d u c t (3 x + 2) (4 x^{2} - 7 x + 1) i s

e x p an d \frac{1}{t ( t - 11 )}

e x p an d (\frac{- x + 10}{3})^{2}

e x p an d \frac{7 s}{( s ^{2} + k ^{2} ) ( s - 1 )}

e x p an d \frac{x - n p}{p ( 1 - p )}