erweitern (3x+3)(x+1)'

Lösung

erweitern

(3 x + 3) (x + 1)^{'}

3 x (x + 1)' + 3 (x + 1)'

Schritte zur Lösung

(3 x + 3) (x + 1)^{'}

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = (x + 1)^{'}, b = 3 x, c = 3

= (x + 1)^{^{'}} 3 x + (x + 1)^{^{'}} 3

= 3 x (x + 1)^{^{'}} + 3 (x + 1)^{^{'}}

e x p an d (e^{x + y} + y e^{y}) d x + (x e^{y} - 1) d y

e x p an d - 3 j (3 j^{2})

e x p an d \frac{( 1000 + n ^{2} ) ^{2}}{1000000}

e x p an d Z ((n - 1) a^{n - 1})

e x p an d f (35 (t - \frac{4}{5})) H (t - \frac{4}{5})