erweitern (2x+1)^3dx

Lösung

erweitern

(2 x + 1)^{3} d x

8 x^{3} d x + 12 x^{2} d x + 6 x d x + d x

Schritte zur Lösung

(2 x + 1)^{3} d x

(2 x + 1)^{3} = 8 x^{3} + 12 x^{2} + 6 x + 1

= (8 x^{3} + 12 x^{2} + 6 x + 1) d x

Setze Klammern

= d x \cdot 8 x^{3} + d x \cdot 12 x^{2} + d x \cdot 6 x + d x \cdot 1

= 8 x^{3} d x + 12 x^{2} d x + 6 x d x + 1 \cdot d x

Multipliziere:

1 \cdot d x = d x

= 8 x^{3} d x + 12 x^{2} d x + 6 x d x + d x

e x p an d (x - 1) 3 ln (x - 1)

e x p an d \frac{( 1 - p ) ( p + p ^{2} - p ^{3} )}{( p + p ^{2} - p ^{3} )}

e x p an d \frac{x + 1}{( x - 1 ) ( x ^{2} + 1 )}

e x p an d (2 y y^{'} (x) + 2 y^{'} (x)) (x^{3} + 2 x - 1)

e x p an d e^{x} (e^{x} - 1)^{2}