erweitern ((3x+1)^{3/2}(18x-4))/(135)

Lösung

erweitern

\frac{( 3 x + 1 ) ^{\frac{3}{2}} ( 18 x - 4 )}{135}

\frac{2 x ( 3 x + 1 ) ^{\frac{3}{2}}}{15} - \frac{4 ( 3 x + 1 ) ^{\frac{3}{2}}}{135}

Schritte zur Lösung

\frac{( 3 x + 1 ) ^{\frac{3}{2}} ( 18 x - 4 )}{135}

Multipliziere aus

(3 x + 1)^{\frac{3}{2}} (18 x - 4) : 18 x (3 x + 1)^{\frac{3}{2}} - 4 (3 x + 1)^{\frac{3}{2}}

= \frac{18 x ( 3 x + 1 ) ^{\frac{3}{2}} - 4 ( 3 x + 1 ) ^{\frac{3}{2}}}{135}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{18 x ( 3 x + 1 ) ^{\frac{3}{2}} - 4 ( 3 x + 1 ) ^{\frac{3}{2}}}{135} = \frac{18 x ( 3 x + 1 ) ^{\frac{3}{2}}}{135} - \frac{4 ( 3 x + 1 ) ^{\frac{3}{2}}}{135}

= \frac{18 x ( 3 x + 1 ) ^{\frac{3}{2}}}{135} - \frac{4 ( 3 x + 1 ) ^{\frac{3}{2}}}{135}

Streiche

\frac{18 x ( 3 x + 1 ) ^{\frac{3}{2}}}{135} : \frac{2 x ( 3 x + 1 ) ^{\frac{3}{2}}}{15}

= \frac{2 x ( 3 x + 1 ) ^{\frac{3}{2}}}{15} - \frac{4 ( 3 x + 1 ) ^{\frac{3}{2}}}{135}

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