展開する (4/(x+3))(4/(x+3))

解

展開する

(\frac{4}{x + 3}) (\frac{4}{x + 3})

\frac{16}{x ^{2} + 6 x + 9}

解答ステップ

(\frac{4}{x + 3}) (\frac{4}{x + 3})

括弧を削除する:

(a) = a

= \frac{4}{x + 3} \cdot \frac{4}{x + 3}

分数を乗じる:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 4}{( x + 3 ) ( x + 3 )}

数を乗じる:

4 \cdot 4 = 16

= \frac{16}{( x + 3 ) ( x + 3 )}

(x + 3) (x + 3) = (x + 3)^{2}

= \frac{16}{( x + 3 ) ^{2}}

(x + 3)^{2} = x^{2} + 6 x + 9

= \frac{16}{x ^{2} + 6 x + 9}