展开 (x^2+4x-2)-(-x^2-2x=4)

解答

展开

(x^{2} + 4 x - 2) - (- x^{2} - 2 x = 4)

2 x^{2} + 6 x - 2 = 4

求解步骤

(x^{2} + 4 x - 2) - (- x^{2} - 2 x = 4)

= (x^{2} + 4 x - 2) - (- x^{2} - 2 \cdot 4 = x)

- (- x^{2} - 2 x = 4) : x^{2} + 2 x = 4

(x^{2} + 4 x - 2) + x^{2} + 2 x = 4

乘开

(x^{2} + 4 x - 2) + x^{2} + 2 x : 2 x^{2} + 6 x - 2

2 x^{2} + 6 x - 2 = 4

e x p an d (1 - e) 4

e x p an d \frac{1}{( 1 + q \cdot e ^{- r \cdot (x - x o)} )}

e x p an d 3 d y + (\frac{1}{4} + 3 x y) d x

e x p an d (- 0.6823)^{7}

\frac{\partial}{\partial u} ((x) (u + b v - x))