展開する (tI-t^2J+(t-1)K,)(2r^2I+6rK)

解

展開する

(t I - t^{2} J + (t - 1) K,) (2 r^{2} I + 6 rK)

2 t II r^{2} + 6 t I Kr - 2 t^{2} I J r^{2} - 6 t^{2} J Kr + K, 2 t I r^{2} - K, 2 \cdot 1 \cdot I r^{2} + K, 6 t Kr - K, 6 \cdot 1 \cdot Kr

解答ステップ

(t I - t^{2} J + (t - 1) K,) (2 r^{2} I + 6 rK)

= (t I - t^{2} J +, K (t - 1)) (2 I r^{2} + 6 Kr)

拡張

(t I - t^{2} J + (t - 1) K,) (2 r^{2} I + 6 rK) : 2 t II r^{2} + 6 t I Kr - 2 t^{2} I J r^{2} - 6 t^{2} J Kr + K (t - 1), 2 I r^{2} + K (t - 1), 6 Kr

= 2 t II r^{2} + 6 t I Kr - 2 t^{2} I J r^{2} - 6 t^{2} J Kr + K (t - 1), 2 I r^{2} + K (t - 1), 6 Kr

拡張

K, 2 I r^{2} (t - 1) : K, 2 t I r^{2} - K, 2 \cdot 1 \cdot I r^{2}

= 2 t II r^{2} + 6 t I Kr - 2 t^{2} I J r^{2} - 6 t^{2} J Kr + K, 2 t I r^{2} - K, 2 \cdot 1 \cdot I r^{2} + K (t - 1), 6 Kr

拡張

K, 6 Kr (t - 1) : K, 6 t Kr - K, 6 \cdot 1 \cdot Kr

= 2 t II r^{2} + 6 t I Kr - 2 t^{2} I J r^{2} - 6 t^{2} J Kr + K, 2 t I r^{2} - K, 2 \cdot 1 \cdot I r^{2} + K, 6 t Kr - K, 6 \cdot 1 \cdot Kr