展开 g(x)(x=2+log_{4}(x+1))

解答

展开

g (x) (x = 2 + lo g_{4} (x + 1))

xg (x) = 2 + lo g_{4} (x + 1) g (x)

求解步骤

g (x) (x = 2 + lo g_{4} (x + 1))

= g (x) (2 = x + lo g_{4} (x + 1))

使用分配律:

a (b + c) = ab + a c

a = g (x), b = x = 2, c = lo g_{4} (x + 1)

g (x) x = 2 + g (x) lo g_{4} (x + 1)

xg (x) = 2 + lo g_{4} (x + 1) g (x)

e x p an d \frac{d}{d s} \frac{1}{( s ( s + 2 ) ^{2} )} \cdot (s + 2)

e x p an d (2 x - y = 2,) (x + y + 3 = 0)

e x p an d (23 - 32) (5 + 43)

e x p an d \frac{s ^{2} + s + 1}{s ^{3} ( s + 1 )}

e x p an d \frac{1}{( x ( x ^{2} + 1 ) )}