展開する a(16,-17,0,0)+b(1,-1,16,17)+c(0,0,-1,-1)

解

展開する

a (16, - 17, 0, 0) + b (1, - 1, 16, 17) + c (0, 0, - 1, - 1)

16 a, - 17 a, 0, 0 + 1 \cdot b, - 1 \cdot b, 16, 17 + 0 \cdot c, 0, - 1 \cdot c, - 1 \cdot c

解答ステップ

a (16, - 17, 0, 0) + b (1, - 1, 16, 17) + c (0, 0, - 1, - 1)

= (16, - 17 \cdot 0 \cdot 0,,) a + (1, - 1 \cdot 16 \cdot 17,,) b + (0 \cdot 0,, - 1, - 1) c

拡張

a (16, - 17, 0, 0) : 16 a, - 17 a, 0, 0

= 16 a, - 17 a, 0, 0 + b (1, - 1, 16, 17) + c (0, 0, - 1, - 1)

拡張

b (1, - 1, 16, 17) : 1 \cdot b, - 1 \cdot b, 16, 17

= 16 a, - 17 a, 0, 0 + 1 \cdot b, - 1 \cdot b, 16, 17 + c (0, 0, - 1, - 1)

拡張

c (0, 0, - 1, - 1) : 0 \cdot c, 0, - 1 \cdot c, - 1 \cdot c

= 16 a, - 17 a, 0, 0 + 1 \cdot b, - 1 \cdot b, 16, 17 + 0 \cdot c, 0, - 1 \cdot c, - 1 \cdot c