erweitern ((3^{(n+1)(n+2)}+65))/(72)

Lösung

erweitern

\frac{( 3 ^{(n + 1) (n + 2)} + 65 )}{72}

\frac{3 ^{n^{2} + 3 n}}{8} + \frac{65}{72}

Schritte zur Lösung

\frac{3 ^{(n + 1) (n + 2)} + 65}{72}

Multipliziere aus

(n + 1) (n + 2) : n^{2} + 3 n + 2

= \frac{3 ^{n^{2} + 3 n + 2} + 65}{72}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 ^{n^{2} + 3 n + 2} + 65}{72} = \frac{3 ^{n^{2} + 3 n + 2}}{72} + \frac{65}{72}

= \frac{3 ^{n^{2} + 3 n + 2}}{72} + \frac{65}{72}

\frac{3 ^{n^{2} + 3 n + 2}}{72} = \frac{3 ^{n^{2} + 3 n}}{8}

= \frac{3 ^{n^{2} + 3 n}}{8} + \frac{65}{72}

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e x p an d e^{a (s - 1)} + e^{b (s - 1)}

e x p an d \frac{4}{s ( x ^{2} - 4 x + 5 ) ( x ^{2} - 1 )}

e x p an d (x y^{2} + b x^{2} y) d x + (x + y) x^{2} d y