展开 2((x+h)-f(x))^2-1

解答

展开

2 ((x + h) - f (x))^{2} - 1

4 x h - 4 x^{2} f - 4 x h f + 2 x^{2} f^{2} + 2 x^{2} + 2 h^{2} - 1

求解步骤

2 ((x + h) - f (x))^{2} - 1

去除括号:

(a) = a

= 2 (x + h - f x)^{2} - 1

(x + h - f x)^{2} = 2 x h - 2 x^{2} f - 2 x h f + x^{2} f^{2} + x^{2} + h^{2}

= 2 (x^{2} f^{2} + x^{2} - 2 x^{2} f + 2 x h - 2 x h f + h^{2}) - 1

乘开

2 (2 x h - 2 x^{2} f - 2 x h f + x^{2} f^{2} + x^{2} + h^{2}) : 4 x h - 4 x^{2} f - 4 x h f + 2 x^{2} f^{2} + 2 x^{2} + 2 h^{2}

= 4 x h - 4 x^{2} f - 4 x h f + 2 x^{2} f^{2} + 2 x^{2} + 2 h^{2} - 1

e x p an d 12 π (36 - r^{2})

e x p an d (i^{3}) (1) (i)

e x p an d 2 e^{x} (x - 1)

e x p an d \frac{1}{( 1 - 8 x ) ^{2}}

e x p an d \frac{( ( 1 - x ) ^{3} ) ^{'} \cdot 2 x ^{2} - ( 1 - x ) ^{3} \cdot ( 2 x ^{2} ) ^{'}}{2 x ^{4}}