展開する 2((x+h)-f(x))^2-1

解

展開する

2 ((x + h) - f (x))^{2} - 1

4 x h - 4 x^{2} f - 4 x h f + 2 x^{2} f^{2} + 2 x^{2} + 2 h^{2} - 1

解答ステップ

2 ((x + h) - f (x))^{2} - 1

括弧を削除する:

(a) = a

= 2 (x + h - f x)^{2} - 1

(x + h - f x)^{2} = 2 x h - 2 x^{2} f - 2 x h f + x^{2} f^{2} + x^{2} + h^{2}

= 2 (x^{2} f^{2} + x^{2} - 2 x^{2} f + 2 x h - 2 x h f + h^{2}) - 1

拡張

2 (2 x h - 2 x^{2} f - 2 x h f + x^{2} f^{2} + x^{2} + h^{2}) : 4 x h - 4 x^{2} f - 4 x h f + 2 x^{2} f^{2} + 2 x^{2} + 2 h^{2}

= 4 x h - 4 x^{2} f - 4 x h f + 2 x^{2} f^{2} + 2 x^{2} + 2 h^{2} - 1