展开 (2(4+x)+e^{-3x}(2-x))/((2-x)(2+x)(4x))

解答

展开

\frac{2 ( 4 + x ) + e ^{- 3 x} ( 2 - x )}{( 2 - x ) ( 2 + x ) ( 4 x )}

\frac{8 + 2 x + 2 e ^{- 3 x} - e ^{- 3 x} x}{16 x - 4 x ^{3}}

求解步骤

\frac{2 ( 4 + x ) + e ^{- 3 x} ( 2 - x )}{( 2 - x ) ( 2 + x ) ( 4 x )}

去除括号:

(a) = a

= \frac{2 ( 4 + x ) + e ^{- 3 x} ( 2 - x )}{( 2 - x ) ( 2 + x ) \cdot 4 x}

乘开

(2 - x) (2 + x) \cdot 4 x : 16 x - 4 x^{3}

= \frac{2 ( x + 4 ) + e ^{- 3 x} ( - x + 2 )}{16 x - 4 x ^{3}}

乘开

2 (4 + x) + e^{- 3 x} (2 - x) : 8 + 2 x + 2 e^{- 3 x} - e^{- 3 x} x

= \frac{8 + 2 x + 2 e ^{- 3 x} - e ^{- 3 x} x}{16 x - 4 x ^{3}}

e x p an d, 3 (x + 1)^{3} + (x + 1)^{2} - 2 (x + 1)

e x p an d \frac{( ( 2 x - 1 ) ^{3} ( 26 - 6 x ) )}{( 4 - x ) ^{3}}

e x p an d \frac{d}{d x} ((x - 2) (x - 5)^{3}) + 5

e x p an d (\frac{2 x - 1}{x + 1})^{2}

e x p an d \frac{2 ( x + 6 )}{( x + 4 ) ( x - 4 )}