展开 (2z(z^2+2z-8))/((z-1)(z+2))

解答

展开

\frac{2 z ( z ^{2} + 2 z - 8 )}{( z - 1 ) ( z + 2 )}

\frac{2 z ^{3} + 4 z ^{2} - 16 z}{z ^{2} + z - 2}

求解步骤

\frac{2 z ( z ^{2} + 2 z - 8 )}{( z - 1 ) ( z + 2 )}

乘开

(z - 1) (z + 2) : z^{2} + z - 2

= \frac{2 z ( z ^{2} + 2 z - 8 )}{z ^{2} + z - 2}

乘开

2 z (z^{2} + 2 z - 8) : 2 z^{3} + 4 z^{2} - 16 z

= \frac{2 z ^{3} + 4 z ^{2} - 16 z}{z ^{2} + z - 2}

e x p an d \frac{e ^{x}}{( 1 - e ^{x} ) ^{2} d x}

e x p an d (8 x^{2} + 4 y) x^{2} + y^{2} = 1

e x p an d \frac{h ( α - ρ )}{α}

e x p an d 3 w^{2} (2 w^{2})

e x p an d \frac{( 3 + i ) ^{4}}{81}