簡約 e^{-0.123/12}(0.65230+(1-0.6523)*2.4)

解

簡約

e^{- 0.12 \cdot \frac{3}{12}} (0.6523 \cdot 0 + (1 - 0.6523) \cdot 2.4)

0.80981 \dots

解答ステップ

e^{- 0.12 \cdot \frac{3}{12}} (0.6523 \cdot 0 + (1 - 0.6523) \cdot 2.4)

指数の規則を適用する:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{0.12 \cdot \frac{3}{12}}} (2.4 (1 - 0.6523) + 0 \cdot 0.6523)

\frac{1}{e ^{0.12 \cdot \frac{3}{12}}} = \frac{1}{e ^{0.03}}

= \frac{1}{e ^{0.03}} (2.4 (1 - 0.6523) + 0 \cdot 0.6523)

0.6523 \cdot 0 = 0

(1 - 0.6523) \cdot 2.4 = 0.83448

= \frac{1}{e ^{0.03}} (0 + 0.83448)

数を足す:

0 + 0.83448 = 0.83448

= 0.83448 \cdot \frac{1}{e ^{0.03}}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 0.83448}{e ^{0.03}}

数を乗じる:

1 \cdot 0.83448 = 0.83448

= \frac{0.83448}{e ^{0.03}}

e^{0.03} = 1.03045 \dots

= \frac{0.83448}{1.03045 \dots}

数を割る:

\frac{0.83448}{1.03045 \dots} = 0.80981 \dots

= 0.80981 \dots