-8<= 1-3(x-2)<13

解答

- 8 \leq 1 - 3 (x - 2) < 13

- 2 < x \leq 5

间隔符号

(- 2, 5]

求解步骤

- 8 \leq 1 - 3 (x - 2) < 13

若

a \leq u < b

，则

a \leq u and u < b

- 8 \leq 1 - 3 (x - 2) and 1 - 3 (x - 2) < 13

- 8 \leq 1 - 3 (x - 2) : x \leq 5

1 - 3 (x - 2) < 13 : x > - 2

合并区间

x \leq 5 and x > - 2

合并重叠的区间

- 2 < x \leq 5

(1 - 0.537) = \frac{x}{\frac{500}{0.55} + 100.02}

x - 2 < 12

f a c t or - 4 x^{3} (y - 2) - 32 (2 - y)

f a c t or 4 x^{2} - 32 x + 64

s im pl i f y \frac{x ^{2} + 5 x y + 6 y ^{2}}{x + 2 y}