(e^{arctan(sqrt(x))})^'

解答

(e^{a r c t a n (x)})^{^{'}}

\frac{e ^{a r c t a n (x)}}{2 x ( x + 1 )}

求解步骤

(e^{a r c t a n (x)})^{'}

使用连锁律:

e^{a r c t a n (x)} (arctan (x))^{'}

= e^{a r c t a n (x)} (arctan (x))^{'}

(arctan (x))^{'} = \frac{1}{2 x ( x + 1 )}

= e^{a r c t a n (x)} \frac{1}{2 x ( x + 1 )}

化简

e^{a r c t a n (x)} \frac{1}{2 x ( x + 1 )} : \frac{e ^{a r c t a n (x)}}{2 x ( x + 1 )}

= \frac{e ^{a r c t a n (x)}}{2 x ( x + 1 )}

e x p an d \frac{( y - 4 ) ^{3}}{y} (4 - y)^{\frac{5}{2}}

s im pl i f y \frac{299792458}{9} \cdot 40 \cdot 1 0^{- 9}

s im pl i f y 8! \cdot 9 c h oos e^{2} \cdot 2!

s im pl i f y y^{\frac{3}{2}}

s im pl i f y 3 4 128 \cdot 2