faktorisieren (x^2+8)^2-36x^2

Lösung

faktorisieren

(x^{2} + 8)^{2} - 36 x^{2}

(x + 2) (x + 4) (x - 2) (x - 4)

Schritte zur Lösung

(x^{2} + 8)^{2} - 36 x^{2}

Vereinfache

36 x^{2} : (6 x)^{2}

= (x^{2} + 8)^{2} - (6 x)^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(x^{2} + 8)^{2} - (6 x)^{2} = ((x^{2} + 8) + 6 x) ((x^{2} + 8) - 6 x)

= ((x^{2} + 8) + 6 x) ((x^{2} + 8) - 6 x)

Apply rule:

(a) = a

(x^{2} + 8) = x^{2} + 8

= (x^{2} + 8 + 6 x) (x^{2} + 8 - 6 x)

= (x^{2} + 6 x + 8) (x^{2} - 6 x + 8)

Faktorisiere

x^{2} + 6 x + 8 : (x + 2) (x + 4)

Faktorisiere

x^{2} - 6 x + 8 : (x - 2) (x - 4)

= (x + 2) (x + 4) (x - 2) (x - 4)

s im pl i f y \frac{3}{\frac{1}{4}}

\frac{4}{7} v + (\frac{1}{7} + \frac{3}{7} v) = 0

\frac{1}{4} (2 - 1)

s im pl i f y 5 \frac{1}{32}

\frac{x - 2}{5 x + 1} \leq \frac{3}{4}