vereinfachen e^{ln(x)+2ln|ln(x)|}

Lösung

vereinfachen

e^{l n (x) + 2 l n ∣ l n (x) ∣}

x ln^{2} (x)

Schritte zur Lösung

e^{l n (x) + 2 l n ∣ l n (x) ∣}

Wende die log Regel an:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln ∣ ln (x) ∣ = ln (∣ ln (x) ∣^{2})

= e^{l n (x) + l n (∣ l n (x) ∣^{2})}

Wende die log Regel an:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (x) + ln (∣ ln (x) ∣^{2}) = ln (x ∣ ln (x) ∣^{2})

= e^{l n (x ∣ l n (x) ∣^{2})}

∣ ln (x) ∣^{2} = ln^{2} (x)

= e^{l n (x l n^{2} (x))}

Wende die log Regel an:

a^{l o g_{a} (b)} = b

= x ln^{2} (x)

s im pl i f y \frac{1}{2} ln (\frac{157}{93})

s im pl i f y ln (x^{2} - 9) - ln (x + 3) + 2 ln (x)

s im pl i f y - ln (5.4 - 3) + 2 ln (5.4 - 2)

s im pl i f y 2 ln (x + 1) - ln (x - 2)

s im pl i f y ln (\frac{2 t ^{2} - t - 6}{t + 1})