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受欢迎的代数 >

5x(x+1)-4=2(x^2+9x+3)

解答

5 x (x + 1) - 4 = 2 (x^{2} + 9 x + 3)

解答

x = 5, x = - \frac{2}{3}

+1

十进制

x = 5, x = - 0.66666 \dots

求解步骤

5 x (x + 1) - 4 = 2 (x^{2} + 9 x + 3)

展开

5 x (x + 1) - 4 : 5 x^{2} + 5 x - 4

展开

2 (x^{2} + 9 x + 3) : 2 x^{2} + 18 x + 6

5 x^{2} + 5 x - 4 = 2 x^{2} + 18 x + 6

将

6

para o lado esquerdo

5 x^{2} + 5 x - 10 = 2 x^{2} + 18 x

将

18 x

para o lado esquerdo

5 x^{2} - 13 x - 10 = 2 x^{2}

将

2 x^{2}

para o lado esquerdo

3 x^{2} - 13 x - 10 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

(- 13)^{2} - 4 \cdot 3 (- 10) = 17

x_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 3}

将解分隔开

x_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 3}, x_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 3}

x = \frac{- ( - 13 ) + 17}{2 \cdot 3} : 5

x = \frac{- ( - 13 ) - 17}{2 \cdot 3} : - \frac{2}{3}

二次方程组的解是:

x = 5, x = - \frac{2}{3}

作图

流行的例子

4 + b^{2} = 2 b

- 4 x^{2} = - 1

x^{2} - 9 x = - 26

(x + 5) (x - 1) = 16

solvefor a,(a-1)^2+(b-2)^2=0

so l v e f or a, (a - 1)^{2} + (b - 2)^{2} = 0