zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

2z^2-2z-12=0

解答

2 z^{2} - 2 z - 12 = 0

解答

z = 3, z = - 2

求解步骤

2 z^{2} - 2 z - 12 = 0

使用求根公式求解

z_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 12) = 10

z_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 2}

将解分隔开

z_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 2}, z_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 2}

z = \frac{- ( - 2 ) + 10}{2 \cdot 2} : 3

z = \frac{- ( - 2 ) - 10}{2 \cdot 2} : - 2

二次方程组的解是:

z = 3, z = - 2

作图

流行的例子

x \cdot x - x = 12

2 x^{2} - 20 + 46 = 0

5 x^{2} - 2 = 38

6 x^{2} = 5 x - 1

(x+1)(x-1)=2(x+5)

(x + 1) (x - 1) = 2 (x + 5)