x^2-x+x^2-2x+x^2-3x=0

解

x^{2} - x + x^{2} - 2 x + x^{2} - 3 x = 0

x = 2, x = 0

解答ステップ

x^{2} - x + x^{2} - 2 x + x^{2} - 3 x = 0

改良

3 x^{2} - 6 x = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 3}

解を分離する

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6}{2 \cdot 3} : 2

x = \frac{- ( - 6 ) - 6}{2 \cdot 3} : 0

二次equationの解:

x = 2, x = 0