x^2+5x-300=0

解

x^{2} + 5 x - 300 = 0

x = 15, x = - 20

解答ステップ

x^{2} + 5 x - 300 = 0

解くとthe二次式

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 300 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 300) = 35

x_{1, 2} = \frac{- 5 \pm 35}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 5 + 35}{2 \cdot 1}, x_{2} = \frac{- 5 - 35}{2 \cdot 1}

x = \frac{- 5 + 35}{2 \cdot 1} : 15

x = \frac{- 5 - 35}{2 \cdot 1} : - 20

二次equationの解:

x = 15, x = - 20