What are the solutions to the equation 7^2+2^2=c^2 ?

The solutions to the equation 7^2+2^2=c^2 are c=sqrt(53),c=-sqrt(53)

Find the zeros of 7^2+2^2=c^2

The zeros of 7^2+2^2=c^2 are c=sqrt(53),c=-sqrt(53)

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7^{2} + 2^{2} = c^{2}

c = 53, c = - 53

Decimal Notation

c = 7.28010 \dots, c = - 7.28010 \dots

Solution steps

7^{2} + 2^{2} = c^{2}

Switch sides

c^{2} = 7^{2} + 2^{2}

Simplify

7^{2} + 2^{2} : 53

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 53, c = - 53

x, y = - 0.00002 x^{2} + 0.0136 x + 0.1399

x, x^{2} + y^{2} = z^{2} (1 - z)

300 = 600 - 3 q^{2}

q^{2} + 11 q + 3 = - 4 q^{2}

2 x^{2} + 8 x + 3 = 0

What are the solutions to the equation 7^2+2^2=c^2 ?
The solutions to the equation 7^2+2^2=c^2 are c=sqrt(53),c=-sqrt(53)
Find the zeros of 7^2+2^2=c^2
The zeros of 7^2+2^2=c^2 are c=sqrt(53),c=-sqrt(53)