3r^2+8r+6=0

解答

3 r^{2} + 8 r + 6 = 0

r = - \frac{4}{3} + i \frac{2}{3}, r = - \frac{4}{3} - i \frac{2}{3}

求解步骤

3 r^{2} + 8 r + 6 = 0

使用求根公式求解

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

化简

8^{2} - 4 \cdot 3 \cdot 6 : 22 i

r_{1, 2} = \frac{- 8 \pm 2 2 i}{2 \cdot 3}

将解分隔开

r_{1} = \frac{- 8 + 2 2 i}{2 \cdot 3}, r_{2} = \frac{- 8 - 2 2 i}{2 \cdot 3}

r = \frac{- 8 + 2 2 i}{2 \cdot 3} : - \frac{4}{3} + i \frac{2}{3}

r = \frac{- 8 - 2 2 i}{2 \cdot 3} : - \frac{4}{3} - i \frac{2}{3}

二次方程组的解是:

r = - \frac{4}{3} + i \frac{2}{3}, r = - \frac{4}{3} - i \frac{2}{3}

so l v e f or x, y^{1} + 3 x^{2} y = x^{2}

3 (g - 4)^{2} = 27

co m pl e t es q u a re 2 x^{2} - 14 x + 10 = 26

f a c t or x^{2} - 14 x + 35 = - 10

so l v e f or x, x (y^{2} + 3) = (y^{2} x^{2}) + 3