What are the solutions to the equation 6x^2-0.2x-0.48=0 ?

The solutions to the equation 6x^2-0.2x-0.48=0 are x= 3/10 ,x=-4/15

Find the zeros of 6x^2-0.2x-0.48=0

The zeros of 6x^2-0.2x-0.48=0 are x= 3/10 ,x=-4/15

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6 x^{2} - 0.2 x - 0.48 = 0

x = \frac{3}{10}, x = - \frac{4}{15}

Decimal Notation

x = 0.3, x = - 0.26666 \dots

Solution steps

6 x^{2} - 0.2 x - 0.48 = 0

Multiply both sides by

100

600 x^{2} - 20 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 600 ( - 48 )}{2 \cdot 600}

(- 20)^{2} - 4 \cdot 600 (- 48) = 340

x_{1, 2} = \frac{- ( - 20 ) \pm 340}{2 \cdot 600}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 340}{2 \cdot 600}, x_{2} = \frac{- ( - 20 ) - 340}{2 \cdot 600}

x = \frac{- ( - 20 ) + 340}{2 \cdot 600} : \frac{3}{10}

x = \frac{- ( - 20 ) - 340}{2 \cdot 600} : - \frac{4}{15}

The solutions to the quadratic equation are:

x = \frac{3}{10}, x = - \frac{4}{15}

x, x^{2} + y^{2} + z^{2} = 5

6 x^{2} - 121 = 0

3 x^{2} + 2 x - 8 = 0

x^{2} - 4 - (x - 1)^{2} - x = x (x - 1) - 8

x^{2} + b x + 8 = 0

What are the solutions to the equation 6x^2-0.2x-0.48=0 ?
The solutions to the equation 6x^2-0.2x-0.48=0 are x= 3/10 ,x=-4/15
Find the zeros of 6x^2-0.2x-0.48=0
The zeros of 6x^2-0.2x-0.48=0 are x= 3/10 ,x=-4/15