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受欢迎的代数 >

2(6t^2-15t+5)=0

解答

2 (6 t^{2} - 15 t + 5) = 0

解答

t = \frac{15 + 105}{12}, t = \frac{15 - 105}{12}

+1

十进制

t = 2.10391 \dots, t = 0.39608 \dots

求解步骤

2 (6 t^{2} - 15 t + 5) = 0

展开

2 (6 t^{2} - 15 t + 5) : 12 t^{2} - 30 t + 10

12 t^{2} - 30 t + 10 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 12 \cdot 10}{2 \cdot 12}

(- 30)^{2} - 4 \cdot 12 \cdot 10 = 2105

t_{1, 2} = \frac{- ( - 30 ) \pm 2 105}{2 \cdot 12}

将解分隔开

t_{1} = \frac{- ( - 30 ) + 2 105}{2 \cdot 12}, t_{2} = \frac{- ( - 30 ) - 2 105}{2 \cdot 12}

t = \frac{- ( - 30 ) + 2 105}{2 \cdot 12} : \frac{15 + 105}{12}

t = \frac{- ( - 30 ) - 2 105}{2 \cdot 12} : \frac{15 - 105}{12}

二次方程组的解是:

t = \frac{15 + 105}{12}, t = \frac{15 - 105}{12}

作图

流行的例子

x^{2} + 7 x = 31

x^{2} + 7 x = 2 x

3 x^{2} - 2 x = - \frac{1}{3}

solvefor x,x^2+z^2=y

so l v e f or x, x^{2} + z^{2} = y

9 x^{2} - x = 4 x + 7 x^{2}